5x^2/3-4x^1/3-1=0

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Solution for 5x^2/3-4x^1/3-1=0 equation: 


x in (-oo:+oo)

(5*x^2)/3-((4*x^1)/3)-1 = 0

(5*x^2)/3+(-4/3)*x-1 = 0

5/3*x^2-4/3*x-1 = 0

DELTA = (-4/3)^2-(-1*5/3*4)

DELTA = 76/9

DELTA > 0

x = ((76/9)^(1/2)+4/3)/(5/3*2) or x = (4/3-(76/9)^(1/2))/(5/3*2)

x = 3/10*((76/9)^(1/2)+4/3) or x = 3/10*(4/3-(76/9)^(1/2))

x in { 3/10*(4/3-(76/9)^(1/2)), 3/10*((76/9)^(1/2)+4/3) }

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